Statistic

COEFFICIENT OF correlation How is the value of the coefficient of correlation determined? We will practice the neckcloth disorder proportionality and Total Asset Turnover balance data, which are reported in circuit jury 1 and Table 2, as an example. Table 1: armory Turnover ratio and Total Asset Turnover Ratio for 11 Years. daysINVENTORY dollar volume RATIO get on ASSET TURNOVER RATIO (X)(Y) 20002.021.43 20012.481.69 20023.011.82 20032.681.85 20043.141.94 20053.101.86 20062.961.83 20072.561.62 20081.661.45 20092.631.64 20103.391.46 TOTAL29.6318.59 Table 2: Deviations from the concoct and Their Products. YEARSINVENTORY, (X)TOTAL ASSET, (Y)x-x ?y-y ?(x-x ?)^2(y-y ?)^2(x-x ?)(y-y ?) 20002.021.43-0.67-0.260.44890.06760.0303 20012.481.69-0.2100.044100 20023.011.820.320.130.10240.01690.0017 20032.681.85-0.010.160.00010.02560 20043.141.940.450.250.20250.06250.0127 20053.101.860.410.170.16810.02890.0049 20062.961.830.270.140.07290.01960.0014 2007 2.561.62-0.13-0.070.01690.00490.0001 20081.661.45-1.03-0.241.06090.05760.0611 20092.631.64-0.06-0.050.00360.00250 20103.391.460.70-0.230.49000.05290.0259 TOTAL29.6318.59002.61040.3390.1381 MEAN x ?= (??x)/n y ?= (??y)/n = 29.63/11 = 18.59/11 = 2.

69 = 1.69 measure DEVIATIONS s_x= ?((??(x-x)^2 )/(n-1)) s_y= ?(???(y-y)?^2/(n-1)) = ?(2.6104/((11-1))) = ?(0.339/((11-1))) = 0.5109 = 0.1841 CORRELATION COEFICIENT r = (???(x-(x ) ? )(y-y ?)?)/((n-1)s_(x ) s_y ) = 0.1381/((11-1)! (0.5109)(0.1841)) = 0.1381/0.9406 = 0.1468 CONCLUSION Yes, there is a little knowledge between the variables. This confirms our reasoning based on the scatter plat mentioned earlier. The value of 0.1468 is fairly close to 0, so we conclude that the railroad tie is little. THE...If you want to get a encompassing essay, order it on our website: BestEssayCheap.com

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